/* Copyright 2014 The Kubernetes Authors. Licensed under the Apache License, Version 2.0 (the "License"); you may not use this file except in compliance with the License. You may obtain a copy of the License at http://www.apache.org/licenses/LICENSE-2.0 Unless required by applicable law or agreed to in writing, software distributed under the License is distributed on an "AS IS" BASIS, WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. See the License for the specific language governing permissions and limitations under the License. */ package serviceaccount import ( "fmt" "strings" apimachineryvalidation "k8s.io/apimachinery/pkg/api/validation" ) const ( ServiceAccountUsernamePrefix = "system:serviceaccount:" ServiceAccountUsernameSeparator = ":" ServiceAccountGroupPrefix = "system:serviceaccounts:" AllServiceAccountsGroup = "system:serviceaccounts" ) // MakeUsername generates a username from the given namespace and ServiceAccount name. // The resulting username can be passed to SplitUsername to extract the original namespace and ServiceAccount name. func MakeUsername(namespace, name string) string { return ServiceAccountUsernamePrefix + namespace + ServiceAccountUsernameSeparator + name } // MatchesUsername checks whether the provided username matches the namespace and name without // allocating. Use this when checking a service account namespace and name against a known string. func MatchesUsername(namespace, name string, username string) bool { if !strings.HasPrefix(username, ServiceAccountUsernamePrefix) { return false } username = username[len(ServiceAccountUsernamePrefix):] if !strings.HasPrefix(username, namespace) { return false } username = username[len(namespace):] if !strings.HasPrefix(username, ServiceAccountUsernameSeparator) { return false } username = username[len(ServiceAccountUsernameSeparator):] return username == name } var invalidUsernameErr = fmt.Errorf("Username must be in the form %s", MakeUsername("namespace", "name")) // SplitUsername returns the namespace and ServiceAccount name embedded in the given username, // or an error if the username is not a valid name produced by MakeUsername func SplitUsername(username string) (string, string, error) { if !strings.HasPrefix(username, ServiceAccountUsernamePrefix) { return "", "", invalidUsernameErr } trimmed := strings.TrimPrefix(username, ServiceAccountUsernamePrefix) parts := strings.Split(trimmed, ServiceAccountUsernameSeparator) if len(parts) != 2 { return "", "", invalidUsernameErr } namespace, name := parts[0], parts[1] if len(apimachineryvalidation.ValidateNamespaceName(namespace, false)) != 0 { return "", "", invalidUsernameErr } if len(apimachineryvalidation.ValidateServiceAccountName(name, false)) != 0 { return "", "", invalidUsernameErr } return namespace, name, nil } // MakeGroupNames generates service account group names for the given namespace func MakeGroupNames(namespace string) []string { return []string{ AllServiceAccountsGroup, MakeNamespaceGroupName(namespace), } } // MakeNamespaceGroupName returns the name of the group all service accounts in the namespace are included in func MakeNamespaceGroupName(namespace string) string { return ServiceAccountGroupPrefix + namespace }