diff --git a/tech/AC.wiki b/tech/AC.wiki index 922cf80..3a4762c 100644 --- a/tech/AC.wiki +++ b/tech/AC.wiki @@ -12,6 +12,8 @@ the power delivery is calculated via For AC, however, we substitute E with the root mean square (RMS) +=== RMS === + The RMS can be any value for different waves, however for the most common type of wave, the sin wave, we can simply *multiply the peak voltage by 0.707*. For example diff --git a/tech/Impedance.wiki b/tech/Impedance.wiki index 9584ca7..672432e 100644 --- a/tech/Impedance.wiki +++ b/tech/Impedance.wiki @@ -19,8 +19,8 @@ signal. The relationship is shown below X,,l,, = 2(pi)fL -Where X,,l,, is the inductive reactance (in Ohms), -f is AC signal frequency (in hz), +Where X,,l,, is the inductive reactance (in Ohms), +f is AC signal frequency (in hz), and L is the inductance (in henery) *Inductors always make voltage lead current* diff --git a/tech/PEP.wiki b/tech/PEP.wiki new file mode 100644 index 0000000..3048052 --- /dev/null +++ b/tech/PEP.wiki @@ -0,0 +1,44 @@ += PEP = + +Peak envelope delivery or PEP is the average power of onc ecomplete RF cycle at +the peak of the singal envelope. It is important to note that it IS NOT the +power at the peak of an RF cycle during a peak of the signal's envelope. + +PEP is used as it is a convient way to portray the max power of an amplitude +modulated signal. + +== Calcuation == + +To calculate PEP, you need to know the [[Impedance]] and [[AC#RMS|RMS]]. +You can also calcuate it using the Peak Envelope Power (PEV), or the peak +amplitude of one side band, or the Peak to Peak voltage (V,,p-p,,). V,,p-p,, +is found by doubling the PEV, or taking the max voltage of both sidebands. + +PEP is euqal to the average power if an amplitude-modulated signal is not +modulated. + + +The way to calculate it is shown below + +PEP = V,,RMS,,^2 / R + +PEP = ((0.707 * V,,p-p,,) / 2)^2 / R + +PEP = (PEV * 0.707)^2 / R + +Where R is the loads [[Impedance]]. For example, + +Peak envelope voltage (PEV) is 50V across a 50ohm load. PEP is + +PEP = (50 * 0.707)^2 / 50 + +PEP = 25W + +A 50ohm load is dissipating a 1200W PEP, the RMS voltage is + +1200 = V,,RMS,,^2 / 50 + +60000 = V,,RMS,,^2 + +244.948 = V,,RMS,, + diff --git a/tech/electronics.wiki b/tech/electronics.wiki index 2b518c7..cf11b1a 100644 --- a/tech/electronics.wiki +++ b/tech/electronics.wiki @@ -39,6 +39,7 @@ Also see == AC/Radio == * [[AC]] +* [[PEP]] * [[Oscillator]] * [[ADC]] * [[DAC]]